The image above breaks down the three components of the piecewise function. Using this information, we can now graph f(x). When x ≥ 2, f(x) is a function and will pass through (2, 1) and (6,3).Make sure to leave (0,5) and (2,5) unfilled since they are not part of the solution. When 0 Since it only applies for 0 and negative numbers, we will only half of the parabola. When x ≤ 0, f(x) becomes a quadratic function with a parabola that passes through the origin and (-2, 4).Let’s first break down the three intervals and identify how the graph of function would look like: Since it extends in both directions, the range of the function is (- ∞, ∞ ) in interval notation. The same reasoning applies to the range of functions. Since the graph covers all values of x, the domain would be all real numbers or (-∞, ∞). The graph above shows the final graph of the piecewise function. Since f(x) = 1 when x = 0, we plot a filled point at (0,1). Make sure to leave the point of origin unfilled. Just make sure that the two points satisfy y = 2x. To graph the linear function, we can use two points to connect the line. Using the graph, determine its domain and range.įor all intervals of x other than when it is equal to 0, f(x) = 2x (which is a linear function). Graph the piecewise function shown below. Let’s evaluate f(49) using the expression.
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